Bending Stress Calculator
Calculate the actual bending stress in a beam based on the applied moment and cross-section properties. Compare against material allowable stress to determine if the beam is adequate. Supports rectangular, square, and circular cross-sections with built-in material properties for wood and steel.
Maximum bending moment applied to the beam
Width of rectangular section
Depth of rectangular section
Diameter of circular section
Section Modulus (circle): S = πd³/32
Section Modulus (square): S = s³/6
Moment of Inertia: I = bd³/12 (rectangle)
Bending Stress: fb = M/S
Safety Factor: SF = Fb/fb
Allowable Moment: Mallow = S × Fb
Where: M = bending moment, S = section modulus,
Fb = allowable bending stress
M = 15,000 × 12 = 180,000 in-lbs
S = 3.5 × 11.25² / 6 = 73.83 in³
fb = 180,000 / 73.83 = 2,438 psi
Fb (DF #2) = 900 psi
Safety Factor = 900 / 2,438 = 0.37
Status: FAILS - Beam is OVERLOADED by 171%
Increase size or use higher grade material.
Need S ≥ 180,000/900 = 200 in³ → 3.5×20.7 or 5.25×15.1
What is bending stress and how is it distributed across a beam?
Bending stress is the internal stress that resists the bending moment applied to a beam. It varies linearly across the cross-section: maximum compressive stress on the top fiber (for a simply supported beam), maximum tensile stress on the bottom fiber, and zero stress at the neutral axis (centroid). The stress distribution follows σ = My/I, where M is the moment, y is the distance from neutral axis, and I is the moment of inertia. The maximum bending stress occurs at the outermost fibers (top and bottom) where y is largest.
What is section modulus and why does it matter?
Section modulus (S = I/c) is a geometric property that directly relates to a beam's bending strength, where I is moment of inertia and c is the distance from neutral axis to extreme fiber. For a rectangular section: S = bd²/6. A larger section modulus means the beam can resist more bending moment with less stress. Doubling beam depth increases section modulus by 4× (d² effect). This is why deeper beams are dramatically stronger in bending than wider ones of the same cross-sectional area.
How do I know if my beam is strong enough for the applied moment?
Compare the actual bending stress (fb) to the allowable bending stress (Fb). For design to be adequate: fb ≤ Fb × adjustment factors. Actual stress: fb = M / S, where M is the maximum moment and S is the section modulus. Allowable stress depends on material: Douglas Fir #2: ~900 psi, Southern Pine #2: ~1000 psi, LVL: ~2600 psi, Steel: ~24,000 psi. The ratio Fb/fb gives the safety factor. A safety factor of 1.0+ is required, with 1.5-2.0 recommended for most applications.
What cross-sectional shapes are strongest in bending?
For bending strength, I-beams and wide-flange shapes are most efficient because they concentrate material at the extreme fibers (top and bottom flanges) where bending stress is highest, while keeping the web thin to reduce weight. The order of efficiency (strength-to-weight ratio for same area): I-beam > rectangular > square > circle. However, rectangular beams are most common in wood construction due to manufacturing simplicity. For steel, W-shapes (wide flange) are standard. The section modulus per unit weight is the key efficiency metric.
🔗 Related Calculators
📐 Formula
Section Modulus (circle): S = πd³/32
Section Modulus (square): S = s³/6
Moment of Inertia: I = bd³/12 (rectangle)
Bending Stress: fb = M/S
Safety Factor: SF = Fb/fb
Allowable Moment: Mallow = S × Fb
Where: M = bending moment, S = section modulus,
Fb = allowable bending stress
📝 Example Calculation
M = 15,000 × 12 = 180,000 in-lbs
S = 3.5 × 11.25² / 6 = 73.83 in³
fb = 180,000 / 73.83 = 2,438 psi
Fb (DF #2) = 900 psi
Safety Factor = 900 / 2,438 = 0.37
Status: FAILS - Beam is OVERLOADED by 171%
Increase size or use higher grade material.
Need S ≥ 180,000/900 = 200 in³ → 3.5×20.7 or 5.25×15.1