Chi-Square Calculator
Calculate Chi-Square (rho�^2) statistic for goodness-of-fit tests. Determine if observed frequencies differ significantly from expected frequencies. Includes p-value and detailed statistical interpretation.
Observed frequency for category 1
Expected frequency for category 1
Observed frequency for category 2
Expected frequency for category 2
Observed frequency for category 3
Expected frequency for category 3
Observed frequency for category 4
Expected frequency for category 4
Observed frequency for category 5
Expected frequency for category 5
Observed frequency for category 6
Expected frequency for category 6
What is the Chi-Square test?
The Chi-Square (rho�^2) test is a statistical test used to determine if there is a significant association between categorical variables or if observed frequencies differ from expected frequencies. It measures the difference between observed and expected data, with larger rho�^2 values indicating greater discrepancy.
How do you calculate the Chi-Square statistic?
Formula: rho�^2 = Σ[(O - E)^2 / E], where O = observed frequency, E = expected frequency, and Σ means sum across all categories. For each category: subtract expected from observed, square the result, divide by expected, then sum all values. Example: O=30, E=25 gives (30-25)^2/25 = 1.0 for that cell.
What are degrees of freedom in Chi-Square tests?
Degrees of freedom (df) = number of categories - 1 for goodness-of-fit tests, or df = (rows - 1) * (columns - 1) for independence tests. Example: A 2*3 contingency table has df = (2-1)*(3-1) = 2. Higher df requires larger rho�^2 values for significance.
How do you interpret Chi-Square results?
Compare rho�^2 statistic to critical value at chosen significance level (alpha, usually 0.05). If rho�^2 > critical value, reject null hypothesis (significant association exists). Alternatively, if p-value < alpha, reject null hypothesis. Example: rho�^2=7.82, df=3, critical value (alpha=0.05)=7.815 → significant result.
What is the difference between Chi-Square goodness-of-fit and independence tests?
Goodness-of-fit tests whether observed frequencies match expected distribution (one variable). Independence tests whether two categorical variables are related (contingency table). Example: Goodness-of-fit: Do dice rolls match expected 1/6? Independence: Is smoking related to lung cancer?
What assumptions must be met for Chi-Square tests?
Requirements: (1) Independent observations, (2) Expected frequency >= 5 in each category (some allow >= 1), (3) Categorical data, (4) Random sampling. If expected frequencies < 5, consider Fisher's exact test or combine categories. Violating assumptions can lead to incorrect conclusions.
What is a p-value in Chi-Square testing?
The p-value is the probability of obtaining a rho�^2 statistic as extreme as observed, assuming null hypothesis is true. Lower p-values indicate stronger evidence against null hypothesis. Standard: p < 0.05 = significant, p < 0.01 = highly significant, p >= 0.05 = not significant. Example: p=0.03 suggests significant relationship.
What are real-world applications of Chi-Square tests?
Medical research (treatment effectiveness), genetics (Mendel's laws), marketing (customer preference vs demographics), quality control (defect rates), social sciences (survey analysis), A/B testing (conversion rates), education (grading distributions), epidemiology (disease association with factors). Widely used for categorical data analysis.
What is the critical value in Chi-Square tests?
The critical value is the threshold from Chi-Square distribution tables based on degrees of freedom and significance level (alpha). If calculated rho�^2 exceeds critical value, result is significant. Example: df=2, alpha=0.05 gives critical value 5.991. rho�^2=6.5 > 5.991 → reject null hypothesis.
Can Chi-Square tests determine causation?
No, Chi-Square tests only detect associations or relationships between variables, not causation. A significant result means variables are related, but doesn't prove one causes the other. Correlation ≠ causation. Example: Ice cream sales and drowning are associated (both increase in summer) but ice cream doesn't cause drowning.